q^2+16q+64=0

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Solution for q^2+16q+64=0 equation: 



q^2+16q+64=0

a = 1; b = 16; c = +64;
Δ = b2-4ac
Δ = 162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{-16}{2}=-8$

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